(Random House) a strong likelihood or chance of something. The relative possibility an event will occur ...the ratio of the number of actual occurrences to the total number of possible occurrences.
(equally probable outcomes) Let S=sample space (set of all possible distinct outcomes). Then the probability of an event =
The probability of an event in an experiment is the proportion (or fraction) of times the event occurs in a very long (theoretically infinite) series of (independent) repetitions of experiment. (e.g. probability of heads=0.4992)
The probability of an event is a "best guess" by a person making the statement of the chances that the event will happen. (e.g. 30% chance of rain)
Definitions1 and 2 are consistent with one another if we are careful in constructing our model.
must be repeatable (at least in theory).
Has several possible distinct outcomes
A single repetition of the experiment is a ``trial''.
The probability of an event A, denoted P(A), is a number between 0 and 1.
(a) roll a fair die
(b) toss a fair coin until the first head appears
(c) Select a female student in Stat 230 and measure her height.
The set of all possible (indivisible) outcomes of a random experiment.
Above examples:
(a) S={1,2,3,4,5,6}
(b) S={H,TH,TTH,TTTH,...}
(c) S={x R;100 x 300 cm.}
S has a finite or a countable number of points in it. (for example (a) and (b) above).
e.g. we write S={} in this case. These "smallest" possible sets in S, are simple events.
Consists of a sample space S and a probability distribution (to be defined) defined on S
Any subset of the sample space (in the case that S is discrete).
Let S={} be a discrete sample space. Then probabilities are numbers attached to the simple events for such that the following two conditions hold:
The set of values
is called a probability distribution on
S.
When the experiment is performed, some simple event in S must occur.
Definition: The probability P(A) of an general event A is the sum of the probabilities for all the simple events that make up A.
An event A made up of two or more simple events is
called a compound event.
for any event A
since =S
Example: Toss a fair coin until the first head appears. S={H,TH,TTH,TTTH,...}. Then etc. The probability of A= "an even number of tosses is required" Probability an odd number of tosses is required is .
Example:
Toss a coin twice. Find the probability of getting 1 head.
Solution 1:
Let S={HH,HT,TH,TT} and assume the simple events each have probability 1/4. Then HT means head on the first toss and tails on the second. Since 1 head occurs for simple events HT and TH, A={HT,TH} we get P(1 head) =2/4=1/2.
Solution 2:
Let S = { 0 heads, 1 head, 2 heads } and assume the simple events each have probability 1/3. Then P(1 head) = 1/3.
Example:
Roll a red die and a green die. Find the probability the total is 6.
Solution:
Let (x,y) represent getting x
on the red die and y on the green die.
All
points in S have probability 1/36.
A={(1,5),(2,4),(3,3),(4,2),(5,1)}
P(A)=5/36.
What if the dice are identical?
............... | |
S has 21 points. P(A)=3/21?
What is the probability that a 5-card poker hand contains four of a kind?
(four twos or four threes, ...etc)
2.7 Machine Recognition of Handwritten Digits. An optical scanner determining which of the digits 0,1,...,9 an individual has written in a square box. The system may of course be wrong
Describe a sample space S that includes points (x,y), where x stands for the number actually written, and y stands for the number that the machine identifies.
Suppose that the machine is asked to identify very large numbers of digits, of which 0,1,...,9 occur equally often, and suppose that the following probabilities apply to the points in your sample space:
p(0,6)=p(6,0)=.004; p(0,0)=p(6,6)=.096 |
p(5,9)=p(9,5)=.005; p(5,5)=p(9,9)=.095 |
p(4,7)=p(7,4)=.002; p(4,4)=p(7,7)=.098 |
p(y,y)=0.100 for y=1,2,3,8 |
Give a table with probabilities for each point (x,y) in S. What fraction of numbers is correctly identified?
If sample space S={} and each simple event has probability 1/n (i.e. is "equally likely"), then a compound event A consisting of r simple events, has probability
Example: Roll 3 fair dice. There are 666=216 possible outcomes, all equally likely. What is the probability of A= "three dice are different numbers"? Number of triples e.g. (1,2,3) with different numbers is 654 so
The Addition Rule:
Suppose we can either do job 1 in p ways or job 2 in
q ways. Then we can do either job 1
or job 2, (not both) in
p+q ways.
The Multiplication Rule:
Suppose we can do job 1 in p ways and an unrelated job 2 in q ways. Then we can do both job 1 and job 2 in pq ways.
n distinct objects are to be "drawn" or ordered from left to right (Order matters objects are drawn without replacement)
The number of ways to arrange n distinct objects in a
row is
n(n-1)(n-2)(2)(1)=n!
The number of ways to arrange r objects selected from
n distinct objects is
n(n-1)(n-2)...(n-r+1)=n
The number of ways to choose r objects from n (a set, i.e. order doesn't matter) is denoted by . For n and r both non-negative integers with
Example:
We form a 4 digit number by randomly selecting and arranging 4 digits from {1, 2, 3,…7} without replacement. Find the probability the number formed is (c) an even number over 3000.
S={1234,1235,...} has points.
Order filled | 2 | 3 | 4 | 1 |
Number of choices | 5 | 5 | 4 | 1 (ends in 2) |
(5541) or
Order filled | 2 | 3 | 4 | 1 |
Number of choices | 4 | 5 | 4 | 2 (ends in 4 or 6) |
Total=
Beware of Double Counting!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Example: (p.26)
Find the probability a bridge hand (13 cards picked at random from a standard deck) has
3 aces
at least 1 ace
A1: P(hand has 1 ace or more) = (is this correct?)
A2: no ace]
Suppose passengers get on an elevator at the basement floor. There are floors above (numbered ..., ) where passengers may get off.
Find the probability
no passenger gets off at floor 1
A="passengers all get off at different floors"
B="all passengers get off at the same floor"
C="no-one gets of at the first two floors"
D="all passengers get off at floors 1 or nine"
G="exactly one person gets of at each of floors 3 and 4"
What assumption(s) underlies your answer to (a)? Comment briefly on how likely it is that the assumption(s) is valid.
e.g. S={1111,1112,...,9999} has
points. Of these
are such all passengers get off on different floors.
The Birthday Problem. Suppose there are persons in a room. Ignoring February 29 and assuming that every person is equally likely to have been born on any of the 365 other days in a year, find the probability that no two persons in the room have the same birthday. Find the numerical value of this probability for. A: =0.411,0.891,0.994 http://www.ship.edu/%7Edeensl/mathdl/stats/Birthday.html
An event A "occurs" if one of the simple events in A occur.
e.g. throw a die, S={1,2,3,4,5,6}
A="Die is
even"={2,4,6}.
Union:
AB
means A OR B (or
possibly both)
occurs.
Intersection:
AB
(usually written as AB in probability) is
shaded.
AB means A
and B both occur.
Complement:
=points in S which are not in
A
means "A does not occur"
EXAMPLE SECTION 4.1: Students finishing 2A Math:
22% have a math average 80%,
24% have a STAT 230 mark 80%,
20% have an overall average 80%,
14% have both a math average and STAT 230 80%,
13% have both an overall average and STAT 230 80%,
10% have all 3 of these averages 80%,
67% have none of these 3 averages 80%.
Find the probability a randomly chosen math student finishing 2A has math and overall averages both 80% and STAT 230 80%.
Events of interest.
A | = | {Math average80%} | |
B | = | {Overall average80%} | |
C | = | {Stat230 80%} |
Find __________________
Events are mutually exclusive (disjoint) if, for all (the empty event)
(at most one of these can ``happen'')
A probability measure is a set function P( defined on subsets A of S (i.e. assigning a real number value P(A) to subsets A such that:
P(S)=1
empty event.
If are mutually exclusive events, ( a finite number or an infinite sequence)
Other rules governing probability models:
For any event A, 0P(A)1
If A and B are two events with AB, then P(A)P(B).
-P(A)
For any two events AB
For any three events AB
Example: Roll a die 3 times. Find the probability of getting at
least one 6.
Then =P(A)+P(B)+P(C)=(it this right?)
Example: A box contains 10 defective chips and 15 good ones. Twelve chips are drawn at random (without replacement). Find an expression for the probability that at most 5 defective chips are drawn.
Let ="Exactly x defective chips are drawn".
Want
P(A)
whereThen
P(A)
Intersection of Events and
Independence
Events A and B are independent if
Indiana Jones: Raiders of the Lost Ark
What is P(AW)?? P(A)=0.3, P(W)=0.4.
What is P(A\W) and when is it the same as P(A)?
Definition: Events A and B are independent if
or if P(A\B)=P(A) where provided denominator is greater than 0.
QUIZ UP TO & INCLUDING SECTION 4.3
Definition. Three or more events AAA are mutually independent if for every choice of
Example: Toss a die twice. Let A = {first toss is a 3} and B = {the total is 7}. Are A and B independent? Change B to B {total is 8}
Why not call events independent if every pair of events is independent?
Two fair coins are tossed. Let A first coin is heads, B = second coin is heads, = we obtain exactly one head. Then A is independent of B and A is independent of Are AB mutually independent?
AB independent implies
A, are independent,
,B are independent
, are independent
We are interested in the probability of the event A but we are given some relevant information, namely that another event B occurred.
Revise the probabilities assigned to points of S in view of this new information. If the information does not effect the relative probability of points in B then the new probabilities of points outside of B should be set to 0 and those within B rescaled to add to 1.
For an event B with P(B)>0, define the conditional probability This is another probability measure on the same sample space S. Note that P(B\B)=1, and P(\B=0.
Multiplication Rule: P(AB)=P(B)P(A\B)
Let A and B be events defined on the same sample space, with P(A)=0.3, P(B)=0.4 and P(A\B)=0.5. Given that event B does not occur, what is the probability of event A?
Three students Jane, Sue and Tom write an exam. Jane has a 90% chance of passing the exam, Sue has a 70% chance of passing and Tom has an 80% chance of passing. If exactly one of the students failed the exam, what is the probability it was Sue?
Note that we are given the event
Let A,B,C,D be events in a sample space such that
A,AB,ABC
have positive probability.
Then
Let be a partition of the sample space S into disjoint (mutually exclusive) events such that S. Let B be an arbitrary event in S. Then
Many methods of spam detection are based on features that appear more
frequently in spam than in regular email. Conditional probability methods are
then used to decide whether an email is spam or not.
Define the following
events associated with a random email message.
B | = | "Message is spam" |
= | "Message is not spam | |
A | = | "Message contains the word Viagra" |
From a study of email messages coming into a certain system it is estimated that P(B)=0.5, P(A\B)=0.2, and P(A\)=0.001. Find P(B\A and P(\A.
If you declared that any email containing the word Viagra was Spam, then find what fraction of regular (non-spam) emails would be incorrectly identified as Spam.
Review: "at least one of the events A,B,C,D"=
"all of the events A,B,C,D"=ABCD
"none of the events A,B,C,D"=
How do we calculate probabilities of the above?
Choosing appropriate Sample spaces: e.g. 3.8, 3.10, 3.11
Example (p. 48):
In an insurance portfolio 10% of the
policy holders are in Class
(high risk), 40% are in Class
(medium risk), and 50% are in Class
(low risk). The probability a Class
policy has a claim in a given year is .10; similar probabilities for Classes
and
are .05 and .02. Find the probability that if a claim is made, it is for a
Class
policy.
Tree- each path represents a sequence of events.
On a branch write the conditional probability of that event given preceding events
The probability at a node of the tree=product of probabilities on the branches leading to the node
= probability of the intersection of the events leading to it