eigenvalues and eigenvectors continued; diagonalization
(Sections 6.2)
diagonalization and similar matrices;diagonalizability of L is equivalent
to the existence of a full set of eigenvectors. Beware: we allow
eigenvalues to be complex!
Problems:
Find the eigenvector basis:
for the matrix
A= [ cos(theta) -sin(theta) ]
[ sin(theta) cos(theta) ]
for
B= [ 0 1 ]
[ -1 0 ]
John and Mary are taking linear algebra. One of the problems in their
homework assignment was to find the nullspace of the 4X5
matrix A. John's answer was that the nullspace is spanned by (-2,
-2, 0, 2, -6), (1, 5, 4, -3, 11), (3, 5, 2, -4, 13), and (0, -2, -2, 1,
-4).
Mary's answer was that the nullspace is spanned by (1, 1, 0, -1,
3), (-2, 0, 2, 1, -2), and (-1, 3, 4, 1, 5). Are their answers
consistent with each other? (See
this directory for
matlab
and
diary
files with solution.)