3.1 Verbal Formulation of the Mathematical Model

 

Imagine that we have a set of 10 schools to be assigned to 10 teachers. In order to determine a mathematical model, we need to define the following variables:

assign (1, 1) = 1 if teacher 1 is assigned to school 1

= 0 otherwise

assign (1, 2) = 1 if teacher 1 is assigned to school 2

= 0 otherwise

etc.

Note that each of these variables can take on the value of 0 (if the assignment is not made) or 1 (if the assignment) is made.

 

In addition to the above variables, we need the following parameters:

utility (1,1) = the utility derived by assigning teacher 1 to school 1 expressed as a score determining by the scoring system. etc.

Max_school (i) = Maximum number of schools that teacher i may attend

Max_teacher (j) = Maximum number of teachers that school j may hire

 

3.2 Basic Formulation

 

Maximize:

utility(1,1) * assign(1,1) + utility(1,2) * assign(1,2) + .... + utility(10,10) * assign(10,10)

Subject to:

assign(i, 1) + assign(i,2) + ..... +assign(i,10) = Max_school (i)

No more than the maximum number of school are taught by teacher i

 

assign(1,j) + assign(2,j) + ..... +assign(10,j) = Max_teacher (j)

No more than the maximum number of teachers are hired by school j

 

Each variable assign(i,j) is (0 or 1)

 

3.3 Solution Summary

 

The optimal solution to the relaxed problem is:

 

school

teacher

1

2

3

4

5

6

7

8

9

10

1

 

 

 

 

 

 

 

 

x

 

2

x

 

 

 

 

 

 

 

 

 

3

 

 

 

 

 

 

 

x

 

 

4

 

 

 

 

 

x

 

 

 

 

5

 

 

 

 

 

 

x

 

 

 

6

 

 

x

 

 

 

 

 

 

 

7

 

 

 

 

 

 

 

 

 

x

8

 

 

 

 

x

 

 

 

 

 

9

 

 

 

x

 

 

 

 

 

 

10

 

x

 

 

 

 

 

 

 

 

 

With a total score of utility of 698.

3.4 Mathematical Model

 

3.4.1 Assumptions

    1. The arrangement of the morning class and afternoon class is assumed to be independent, i.e., the same teacher can stay in the same school in the morning and the afternoon.
    2. The scoring system simply multiplies teacher i’s score for school j and school j’s score for teacher i. Our objective will then be to optimize the total score for all 10 schools.
    3. Each teacher is assigned to only one school at each of the morning and afternoon period, and each period for any one school can only be taught by one teacher.

 

3.4.2 Index Sets and Variables

I: The set of 10 teachers

J: The set of 10 schools

X(I,J) is the assignment of teacher I to school J

U(I,J) is the utility of teacher I with school J

Z: The objective function

 

3.4.3 Data

The following data is obtained by from the result of a survey, on which each teacher must rank the 10 schools according to their preferences, from 1 to 10, where 1 indicates the least preferred, and 10 indicates the most preferred. Similar data is also obtained by survey the 10 schools on these teachers. The results are then combined by multiplying the scores for each school-teacher pair, which forms the basis of the data of our study.

Preferences of Schools by Each Teacher:

Teacher

1

2

3

4

5

6

7

8

9

10

1

10

8

2

2

8

7

8

2

2

1

2

2

10

8

5

5

6

9

1

10

9

3

5

1

9

8

3

9

6

3

7

4

4

8

3

1

3

4

3

5

4

5

10

School

5

4

4

7

6

7

8

1

9

8

3

6

7

6

5

9

10

5

7

8

3

2

7

3

5

4

4

9

2

4

5

1

5

8

6

7

6

10

2

1

3

10

6

6

9

9

9

10

1

1

10

2

6

4

8

10

1

2

3

7

6

4

10

7

9

7

 

Evaluation of Teacher's performance by Each School:

School

1

2

3

4

5

6

7

8

9

10

1

1

2

3

7

6

4

10

7

9

7

2

4

4

7

6

7

8

1

9

8

3

3

7

6

5

9

10

5

7

8

4

2

4

10

8

2

2

8

7

8

2

2

1

Teacher

5

2

10

8

5

5

6

9

1

10

9

6

5

1

9

8

3

9

6

3

7

4

7

8

3

1

3

4

3

5

4

5

10

8

3

5

4

4

9

2

4

5

1

5

9

6

7

6

10

2

1

3

10

6

6

10

9

9

10

1

1

10

2

6

3

8

Combined score of the teachers' and schools' preference

School

1

2

3

4

5

6

7

8

9

10

1

10

4

15

56

24

28

30

42

81

7

2

32

40

7

18

28

48

5

63

72

6

3

14

48

45

9

70

25

28

48

40

6

4

20

40

16

6

48

63

32

20

2

7

Teacher

5

16

50

24

20

35

60

81

2

10

54

6

35

6

81

24

24

45

12

3

70

16

7

64

27

6

15

4

21

20

12

10

100

8

6

5

12

16

81

16

20

50

6

35

9

12

70

42

50

16

3

3

60

24

54

10

9

81

40

10

3

20

10

36

24

56

 

3.4.4 Program

Objective Function

Maximize: S(i,j) uij*xij

Constraints

S(j) xij = 1 for all i

No more than 1 school is taught by teacher i

S(i) xij = 1for all j

No more than the 1 teacher assigned to school j

xij = 0 or 1 for all i, j

4.1 Verbal Formulation of the Mathematical Model

 

In the original problem, 10 teachers are assigned to two sessions at 10 different schools. Also, in this case, we take into account the requirement that each teacher must go to a different school in the morning and in the afternoon session.

 

Our goal is to develop a model which determines how to assign teachers to the different sessions at different schools, subject to the following requirements:

 

- Each teacher is assigned to no more than one school in each session

- Each session at a particular school is taught by exactly one teacher

- Each teacher must go to a different school in the morning and in the afternoon session

 

In this problem, a new index must be defined to indicate the two different sessions. Basically, we have a set of two sessions (a.m., p.m.) at 10 schools that must be assigned to 10 teachers. In order to determine a mathematical model, we need to define the following variables:

 

assign (1, am, 1) = 1 if teacher 1 is assigned to the morning session at school 1

= 0 otherwise

 

assign (1, am, 2) = 1 if teacher 1 is assigned to the morning session at school 2

= 0 otherwise

etc.

Note that each of these variables can take on the value of 0 (if the assignment is not made) or 1 (if the assignment) is made.

In addition to the above variables, we need the following parameters:

 

utility (1,am, 1) = the utility derived by assigning teacher 1 to school 1 expressed as a score determining by the scoring system.

etc.

 

Max_school_am (i, am) = Max. # of morning session teacher i may attend

Max_school_pm (i, pm) = Max. # of afternoon session teacher i may attend

Max_teacher_am (am, j) = Max. # of teacher assigned to each morning session

at school j

Max_teacher_pm (pm, j) = Max. # of teacher assigned to each afternoon session

at school j

 

 

4.2 Basic Formulation

 

Maximize:

utility(1, am, 1) * assign(1, am,1) + utility(1, am, 2) * assign(1, am, 2) + ....

+ utility(10, pm, 10) * assign(10, pm, 10)

Subject to:

assign(i, am, 1) + assign(i, am, 2) + ..... +assign(i, am, 10) = Max_school_am (i, am)

No more than the maximum number of morning session are taught by teacher i

 

 

assign(i, pm, 1) + assign(i, pm, 2) + ..... +assign(i, pm, 10) = Max_school_pm (i, pm)

No more than the maximum number of afternoon session are taught by teacher i

 

assign(1, am, j) + assign(2, am, j) + ..... +assign(10, am, j) = Max_teacher_am (am, j)

No more than the maximum number of teachers are assigned to the morning session at school j

 

assign(1, pm, j) + assign(2, pm, j) + ..... +assign(10, pm, j) = Max_teacher_pm (pm, j)

No more than the maximum number of teachers are assigned to the afternoon session at school j

 

assign (i, pm, j) £ 1- assign (i, am, j)

Ensure that each teacher attends the morning and afternoon sessions at different school.

 

Note that if teacher i is already assigned to the morning session at school j, the value for assign (i, am, j) will be 1. The above equation has the effect of enforcing assign (i, pm, j) to be 0 and hence ensures that the teacher is not assigned to the afternoon session at the same school

 

Each variable assign(i,k,j) is (0 or 1)

 

 

4.3 Solution Summary

 

The optimal solution to the original problem:

 

school

teacher

1

2

3

4

5

6

7

8

9

10

1

 

 

 

A

 

 

 

 

P

 

2

 

 

 

 

 

 

 

P

A

 

3

 

 

P

 

A

 

 

 

 

 

4

 

 

 

 

 

A

P

 

 

 

5

 

 

 

 

 

P

A

 

 

 

6

P

 

A

 

 

 

 

 

 

 

7

A

 

 

 

 

 

 

 

 

P

8

 

 

 

 

P

 

 

A

 

 

9

 

A

 

P

 

 

 

 

 

 

10

 

P

 

 

 

 

 

 

 

A

 

With the optimal objective value of 1291.

 

 

 

4.4 Mathematical Model

 

4.4.1 Assumptions

    1. Each teacher must go to a different school in the morning and in the afternoon session.
    2. The scoring system simply multiplies teacher i’s score for school j and school j’s score for teacher i. Our objective will then be to optimize the total score for all 10 schools. Also, the rating for the morning session is identical to the rating for the afternoon session.
    3. Each teacher is assigned to only one school at each of the morning and afternoon period, and each period for any one school can only be taught by one teacher.

 

4.4.2 Index Sets and Variables

I: The set of 10 teachers

J: The set of 10 schools

K: The set of two different sessions

 

X(I,K,J) is the assignment of teacher I to the session K at school J

U(I,K,J) is the utility of teacher I teaching session K at school

 

Z: The objective function

 

4.4.3 Data

See Data for the relaxed problem as outlined in subsection 3.4.3.

  

4.4.4 Program

Objective Function

Maximize: S(i,k,j) uikj*xikj

Constraints

S(k,j) xikj = 1 for all k,j

No more than 1 teacher is assigned to the k session at school j

S(i,k) xikj = 1 for all i,k

No more than 1 session at school j is assigned to the teacher i

x(i, pm, j) £ 1- x(i, am, j)

Ensure that teacher i is not assigned to the afternoon session at the same school

 

xikj = 0 or 1 for all i, k,j