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Problem 3.5

The conclusion for this problem can be done without the preliminary problem and without the hint.

With the usual notation:

\begin{displaymath}
g=\nabla f(x_k), \quad B = B_k, \quad p=-B^{-1} g,
\quad \vert\vert B^{-1}\vert\vert \vert\vert B\vert\vert \leq M;
\end{displaymath}

and

\begin{displaymath}
y=B^{-\frac 12} g, \quad g=B^{\frac 12} y.
\end{displaymath}

Then

\begin{eqnarray*}
\cos \theta &=& \frac{g^t B^{-1} g}{\vert\vert B^{-1}g\vert\vert \vert\vert g\vert\vert} \\
\end{eqnarray*}



and

\begin{eqnarray*}
\frac 1{\cos \theta} &=& \frac{\vert\vert B^{-1}g\vert\vert \...
...vert B^{\frac 12}\vert\vert \\
& \leq & M^{-\frac 12} \leq M.
\end{eqnarray*}





Henry Wolkowicz
2001-02-04